0=-4.9t^2+60

Solution for 0=-4.9t^2+60 equation:

0=-4.9t^2+60

We move all terms to the left:

0-(-4.9t^2+60)=0

We add all the numbers together, and all the variables

-(-4.9t^2+60)=0

We get rid of parentheses

4.9t^2-60=0

a = 4.9; b = 0; c = -60;
Δ = b2-4ac
Δ = 02-4·4.9·(-60)
Δ = 1176
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1176}=\sqrt{196*6}=\sqrt{196}*\sqrt{6}=14\sqrt{6}$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-14\sqrt{6}}{2*4.9}=\frac{0-14\sqrt{6}}{9.8}
=-\frac{14\sqrt{6}}{9.8}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+14\sqrt{6}}{2*4.9}=\frac{0+14\sqrt{6}}{9.8}
=\frac{14\sqrt{6}}{9.8}
$